using System;

using System.Linq;

​

public class Program

{

    public static void Main()

    {

        start:

            Console.WriteLine("Welcome! 10 Random postive intgers Will Be Generated From 1 - 100 ");

        Random r = new Random();

        int[] number;

        number = new int[10];

        Console.WriteLine();

        Console.WriteLine("The intgers are ....... ");

        for (int i = 0; i < 10; i++)

        {

            number[i] = r.Next(1, 101);

            Console.Write(number[i] + " ");

        }

​

        Console.WriteLine();

        Console.WriteLine();

        Console.WriteLine("The previous integers sorted from smallest to largest is : ");

        Array.Sort(number);

        foreach (int random in number)

        {

            Console.Write(random + " ");

        }

​

        Console.WriteLine();

        Console.WriteLine();

        Console.WriteLine("The average of these integers is:");

        Console.WriteLine(number.Average());

        Console.WriteLine();

        Console.WriteLine("The median of these integers is: ");

        Console.WriteLine(Median(number));

        Console.WriteLine("Would you like to try again (y/n)");

        string choice = Console.ReadLine();

        if (choice == "y" || choice == "Y")

        {

            Console.Clear();

            goto start;

        }

        else

        {

            Console.Clear();

        }

    }

​

    static private int Median(int[] array)

    {

        int[] tempArray = array;

        int count = tempArray.Length;

        Array.Sort(tempArray);

        int medianValue = 0;

        if (count % 2 == 0)

        {

            int middleElement1 = tempArray[(count / 2) - 1];

            int middleElement2 = tempArray[(count / 2)];

            medianValue = (middleElement1 + middleElement2) / 2;

        }

        else

        {

            medianValue = tempArray[(count / 2)];

        }

​

        return medianValue;

    }

}