using System;

public class Program

{

    public static void Main()

    {

        /*

        * CODE CHALLENGE:

        * If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

        * Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in. Additionally, if the number is negative, return 0 (for languages that do have them).

        * Note: If the number is a multiple of both 3 and 5, only count it once.

        */

        /*

        // FIRST TRY:

        Console.WriteLine(Solution(10));

        static int Solution(int value) => (value <= 0) ? 0 : AddNums(value);

        static int AddNums(int num)

        {

            int sum = 0;

            Console.WriteLine($"Starting w/ [{num}]...");

            do

            {

                num = --num;

                if (num % 5 == 0 && num != 0)

                {

                    Console.WriteLine($" > Num {num} is divisible by 5.");

                    sum += num;

                }

                else if (num % 3 == 0 && num !=0)

                {

                    Console.WriteLine($" > Num {num} is divisible by 3.");

                    sum += num;

                }

            }

            while (num > 0);

            Console.WriteLine("=> Sum of all nums is...");

            return sum;

        }*/

        // SECOND TRY:

        Console.WriteLine(Solution(10));

        static int Solution(int value)

        {

            int sum = 0;

            Console.WriteLine($"Starting w/ a value of {value}...");

            while (--value > 0)

            {

                if (value % 5 == 0 || value % 3 == 0)

                {

                    Console.WriteLine($"  > A divided Num of {value} was found.");

                    sum += value;

                }

            }

            Console.WriteLine(" => The Sum of all Nums is...");

            return sum;

        };

    }

}