using Newtonsoft.Json.Linq;
public static void Main()
""8c316aca-b930-421f-851c-17d618b61fa1"",
""8c316aca-b930-421f-851c-17d618b61fa1"",
""a23shaga-2wd3-fky6-851c-43524fbfgsa""
JArray jArray = JArray.Parse(json);
var x = jArray.ToObject<string[]>().Distinct();
Console.WriteLine(string.Join("\n", x));