Question39738714 Selectively use default JSON converter

CSharp · Console

/Program.cs

using System;
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Runtime.Serialization.Formatters;
using System.IO;
using System.Data;
using System.Xml.Serialization;
using System.Runtime.Serialization;

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using Newtonsoft.Json.Converters;
using Newtonsoft.Json.Serialization;		
					
    public class NoConverter : JsonConverter
    {
		public override bool CanConvert(Type objectType)
        {
	        // Note - not called when attached directly via [JsonConverter(typeof(NoConverter))]
            throw new NotImplementedException();
        }

        public override bool CanRead { get { return false; } }

        public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
        {
            throw new NotImplementedException();
        }

        public override bool CanWrite { get { return false; } }

        public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
        {
            throw new NotImplementedException();
        }
    }

    public enum Foo { A, B, C }
	
	[JsonConverter(typeof(NoConverter))]
	public enum FooAlwaysAsInteger { A, B, C }

	public class RootObject
	{
		[JsonConverter(typeof(NoConverter))]
		public Foo FooAsInteger { get; set; }
		
		public Foo FooAsString { get; set; }
		
		public FooAlwaysAsInteger Foo2AlwaysAsInteger { get; set; }
	}
	

	public class Program
	{
		public static void Main()
		{
			var root = new RootObject { FooAsInteger = Foo.B, FooAsString = Foo.B, Foo2AlwaysAsInteger = FooAlwaysAsInteger.C };
			
			var json = JsonConvert.SerializeObject(root, Formatting.Indented, new StringEnumConverter());
			
			Console.WriteLine(json);
		}
	}